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/2x-3=2x-5.
We move all terms to the left:
/2x-3-(2x-5.)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
/2x-(2x-5)-3=0
We get rid of parentheses
/2x-2x+5-3=0
We multiply all the terms by the denominator
-2x*2x+5*2x-3*2x+=0
We add all the numbers together, and all the variables
-2x*2x+5*2x-3*2x=0
Wy multiply elements
-4x^2+10x-6x=0
We add all the numbers together, and all the variables
-4x^2+4x=0
a = -4; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-4)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-4}=\frac{-8}{-8} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-4}=\frac{0}{-8} =0 $
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