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/2x+6=4x+10
We move all terms to the left:
/2x+6-(4x+10)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
/2x-4x-10+6=0
We multiply all the terms by the denominator
-4x*2x-10*2x+6*2x+=0
We add all the numbers together, and all the variables
-4x*2x-10*2x+6*2x=0
Wy multiply elements
-8x^2-20x+12x=0
We add all the numbers together, and all the variables
-8x^2-8x=0
a = -8; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·(-8)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*-8}=\frac{0}{-16} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*-8}=\frac{16}{-16} =-1 $
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