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/2x+5x-11=-46*
We move all terms to the left:
/2x+5x-11-(-46*)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
/2x+5x-11-0=0
We add all the numbers together, and all the variables
5x+/2x-11=0
We multiply all the terms by the denominator
5x*2x-11*2x+=0
We add all the numbers together, and all the variables
5x*2x-11*2x=0
Wy multiply elements
10x^2-22x=0
a = 10; b = -22; c = 0;
Δ = b2-4ac
Δ = -222-4·10·0
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-22}{2*10}=\frac{0}{20} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+22}{2*10}=\frac{44}{20} =2+1/5 $
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