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/2x+3x=45
We move all terms to the left:
/2x+3x-(45)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
3x+/2x-45=0
We multiply all the terms by the denominator
3x*2x-45*2x+=0
We add all the numbers together, and all the variables
3x*2x-45*2x=0
Wy multiply elements
6x^2-90x=0
a = 6; b = -90; c = 0;
Δ = b2-4ac
Δ = -902-4·6·0
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8100}=90$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-90}{2*6}=\frac{0}{12} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+90}{2*6}=\frac{180}{12} =15 $
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