/2b=16-2b

Solution for /2b=16-2b equation:

/2b=16-2b

We move all terms to the left:

/2b-(16-2b)=0


Domain of the equation: 2b!=0

b!=0/2

b!=0

b∈R


We add all the numbers together, and all the variables

/2b-(-2b+16)=0

We get rid of parentheses

/2b+2b-16=0

We multiply all the terms by the denominator


2b*2b-16*2b+=0

We add all the numbers together, and all the variables

2b*2b-16*2b=0

Wy multiply elements

4b^2-32b=0

a = 4; b = -32; c = 0;
Δ = b2-4ac
Δ = -322-4·4·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-32}{2*4}=\frac{0}{8}
=0
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+32}{2*4}=\frac{64}{8}
=8
$