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/2(x+4)-3x=-8
We move all terms to the left:
/2(x+4)-3x-(-8)=0
Domain of the equation: 2(x+4)!=0We add all the numbers together, and all the variables
x∈R
-3x+/2(x+4)+8=0
We multiply all the terms by the denominator
-3x*2(x+4)+8*2(x+4)+=0
We add all the numbers together, and all the variables
-3x*2(x+4)+8*2(x+4)=0
Wy multiply elements
-6x^2(x+16x(x=0
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