/110b-28+10b=26b-30

Solution for /110b-28+10b=26b-30 equation:

/110b-28+10b=26b-30

We move all terms to the left:

/110b-28+10b-(26b-30)=0


Domain of the equation: 110b!=0

b!=0/110

b!=0

b∈R


We add all the numbers together, and all the variables

10b+/110b-(26b-30)-28=0

We get rid of parentheses

10b+/110b-26b+30-28=0

We multiply all the terms by the denominator


10b*110b-26b*110b+30*110b-28*110b+=0

We add all the numbers together, and all the variables

10b*110b-26b*110b+30*110b-28*110b=0

Wy multiply elements

1100b^2-2860b^2+3300b-3080b=0

We add all the numbers together, and all the variables

-1760b^2+220b=0

a = -1760; b = 220; c = 0;
Δ = b2-4ac
Δ = 2202-4·(-1760)·0
Δ = 48400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{48400}=220$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(220)-220}{2*-1760}=\frac{-440}{-3520}
=1/8
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(220)+220}{2*-1760}=\frac{0}{-3520}
=0
$