/10a+2-5(a+1)=5a-3

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Solution for /10a+2-5(a+1)=5a-3 equation: 



/10a+2-5(a+1)=5a-3

We move all terms to the left:

/10a+2-5(a+1)-(5a-3)=0



Domain of the equation: 10a!=0

a!=0/10

a!=0

a∈R



We multiply parentheses

/10a-5a-(5a-3)-5+2=0

We get rid of parentheses

/10a-5a-5a+3-5+2=0

We multiply all the terms by the denominator


-5a*10a-5a*10a+3*10a-5*10a+2*10a+=0

We add all the numbers together, and all the variables

-5a*10a-5a*10a+3*10a-5*10a+2*10a=0

Wy multiply elements

-50a^2-50a^2+30a-50a+20a=0

We add all the numbers together, and all the variables

-100a^2=0

a = -100; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-100)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{0}{-200}=0$

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