/10(x+50)=-3x-13+4x

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Solution for /10(x+50)=-3x-13+4x equation: 



/10(x+50)=-3x-13+4x

We move all terms to the left:

/10(x+50)-(-3x-13+4x)=0



Domain of the equation: 10(x+50)!=0

x∈R



We add all the numbers together, and all the variables

/10(x+50)-(x-13)=0

We get rid of parentheses

/10(x+50)-x+13=0

We multiply all the terms by the denominator


-x*10(x+50)+13*10(x+50)+=0

We add all the numbers together, and all the variables

-x*10(x+50)+13*10(x+50)=0

Wy multiply elements

-10x^2(x+130x(x=0

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