/-4(b+1)+2b=3(2b-1)

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Solution for /-4(b+1)+2b=3(2b-1) equation: 



/-4(b+1)+2b=3(2b-1)

We move all terms to the left:

/-4(b+1)+2b-(3(2b-1))=0

We add all the numbers together, and all the variables

2b-4(b+1)-(3(2b-1))+1=0

We multiply parentheses

2b-4b-(3(2b-1))-4+1=0



We calculate terms in parentheses: -(3(2b-1)), so:

3(2b-1)

We multiply parentheses

6b-3

Back to the equation:

-(6b-3)



We add all the numbers together, and all the variables

-2b-(6b-3)-3=0

We get rid of parentheses

-2b-6b+3-3=0

We add all the numbers together, and all the variables

-8b=0

b=0/-8

b=0

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