/(Ax12)+32=180

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Solution for /(Ax12)+32=180 equation: 



/(A12)+32=180

We move all terms to the left:

/(A12)+32-(180)=0



Domain of the equation: A12!=0

A^12!=0/

A^12!=12√0

A!=0

A∈R



We add all the numbers together, and all the variables

/A12-148=0

We multiply all the terms by the denominator


-148*A12+=0

We add all the numbers together, and all the variables

-148A^12=0

We do not support eApression: A^12

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