/(6+v)(4v+2)=0

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Solution for /(6+v)(4v+2)=0 equation: 



/(6+v)(4v+2)=0



Domain of the equation: (6+v)(4v+2)!=0

We move all terms containing v to the left, all other terms to the right

v)(4v!=-8

v∈R



We add all the numbers together, and all the variables

/(v+6)(4v+2)=0

We multiply parentheses ..

/(+4v^2+2v+24v+12)=0

We multiply all the terms by the denominator


=0

v=0/1

v=0

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