.8p2-4p=0

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Solution for .8p2-4p=0 equation: 



.8p^2-4p=0

a = .8; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·.8·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$


$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*.8}=\frac{0}{1.6}
=0
$


$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*.8}=\frac{8}{1.6}
=5
$

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