.75x+3(x+20)=2+.5(x-2)

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Solution for .75x+3(x+20)=2+.5(x-2) equation: 



.75x+3(x+20)=2+.5(x-2)

We move all terms to the left:

.75x+3(x+20)-(2+.5(x-2))=0

We multiply parentheses

.75x+3x-(2+.5(x-2))+60=0



We calculate terms in parentheses: -(2+.5(x-2)), so:

2+.5(x-2)

determiningTheFunctionDomain
.5(x-2)+2

We multiply parentheses

0.5x-1+2

We add all the numbers together, and all the variables

0.5x+1

Back to the equation:

-(0.5x+1)



We add all the numbers together, and all the variables

3.75x-(0.5x+1)+60=0

We get rid of parentheses

3.75x-0.5x-1+60=0

We add all the numbers together, and all the variables

3.25x+59=0

We move all terms containing x to the left, all other terms to the right

3.25x=-59

x=-59/3.25

x=-18+0.5/3.25

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