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.75x+12=1/5x-10
We move all terms to the left:
.75x+12-(1/5x-10)=0
Domain of the equation: 5x-10)!=0We get rid of parentheses
x∈R
.75x-1/5x+10+12=0
We multiply all the terms by the denominator
(.75x)*5x+10*5x+12*5x-1=0
We add all the numbers together, and all the variables
(+.75x)*5x+10*5x+12*5x-1=0
We multiply parentheses
5x^2+10*5x+12*5x-1=0
Wy multiply elements
5x^2+50x+60x-1=0
We add all the numbers together, and all the variables
5x^2+110x-1=0
a = 5; b = 110; c = -1;
Δ = b2-4ac
Δ = 1102-4·5·(-1)
Δ = 12120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12120}=\sqrt{4*3030}=\sqrt{4}*\sqrt{3030}=2\sqrt{3030}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(110)-2\sqrt{3030}}{2*5}=\frac{-110-2\sqrt{3030}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(110)+2\sqrt{3030}}{2*5}=\frac{-110+2\sqrt{3030}}{10} $
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