.5(6x-3)=4(1+x)

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Solution for .5(6x-3)=4(1+x) equation: 



.5(6x-3)=4(1+x)

We move all terms to the left:

.5(6x-3)-(4(1+x))=0

We add all the numbers together, and all the variables

.5(6x-3)-(4(x+1))=0

We multiply parentheses

3x-(4(x+1))-1.5=0



We calculate terms in parentheses: -(4(x+1)), so:

4(x+1)

We multiply parentheses

4x+4

Back to the equation:

-(4x+4)



We get rid of parentheses

3x-4x-4-1.5=0

We add all the numbers together, and all the variables

-1x-5.5=0

We move all terms containing x to the left, all other terms to the right

-x=5.5

x=5.5/-1

x=-5+0.5/1

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