.40x+.60(80-x)=36

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Solution for .40x+.60(80-x)=36 equation: 



.40x+.60(80-x)=36

We move all terms to the left:

.40x+.60(80-x)-(36)=0

We add all the numbers together, and all the variables

.40x+.60(-1x+80)-36=0

We multiply parentheses

.40x-0.6x+48-36=0

We add all the numbers together, and all the variables

-0.2x+12=0

We move all terms containing x to the left, all other terms to the right

-0.2x=-12

x=-12/-0.2

x=+60

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