.3(y-2)=.4(1+y)

Solution for .3(y-2)=.4(1+y) equation:

Simplifying
0.3(y + -2) = 0.4(1 + y)

Reorder the terms:
0.3(-2 + y) = 0.4(1 + y)
(-2 * 0.3 + y * 0.3) = 0.4(1 + y)
(-0.6 + 0.3y) = 0.4(1 + y)
-0.6 + 0.3y = (1 * 0.4 + y * 0.4)
-0.6 + 0.3y = (0.4 + 0.4y)

Solving
-0.6 + 0.3y = 0.4 + 0.4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-0.4y' to each side of the equation.
-0.6 + 0.3y + -0.4y = 0.4 + 0.4y + -0.4y

Combine like terms: 0.3y + -0.4y = -0.1y
-0.6 + -0.1y = 0.4 + 0.4y + -0.4y

Combine like terms: 0.4y + -0.4y = 0.0
-0.6 + -0.1y = 0.4 + 0.0
-0.6 + -0.1y = 0.4

Add '0.6' to each side of the equation.
-0.6 + 0.6 + -0.1y = 0.4 + 0.6

Combine like terms: -0.6 + 0.6 = 0.0
0.0 + -0.1y = 0.4 + 0.6
-0.1y = 0.4 + 0.6

Combine like terms: 0.4 + 0.6 = 1
-0.1y = 1

Divide each side by '-0.1'.
y = -10

Simplifying
y = -10