.20(10)=0.05x+0.40(10-x)

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Solution for .20(10)=0.05x+0.40(10-x) equation: 



.20(10)=0.05x+0.40(10-x)

We move all terms to the left:

.20(10)-(0.05x+0.40(10-x))=0

We add all the numbers together, and all the variables

-(0.05x+0.40(-1x+10))+.2010=0

We add all the numbers together, and all the variables

-(0.05x+0.40(-1x+10))+0.201=0



We calculate terms in parentheses: -(0.05x+0.40(-1x+10)), so:

0.05x+0.40(-1x+10)

We multiply parentheses

0.05x-0.4x+4

We add all the numbers together, and all the variables

-0.35x+4

Back to the equation:

-(-0.35x+4)



We get rid of parentheses

0.35x-4+0.201=0

We add all the numbers together, and all the variables

0.35x-3.799=0

We move all terms containing x to the left, all other terms to the right

0.35x=3.799

x=3.799/0.35

x=10+0.299/0.35

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