.2(b+2)-5(2b-3)=3

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Solution for .2(b+2)-5(2b-3)=3 equation: 



.2(b+2)-5(2b-3)=3

We move all terms to the left:

.2(b+2)-5(2b-3)-(3)=0

We multiply parentheses

0.2b-10b+0.4+15-3=0

We add all the numbers together, and all the variables

-9.8b+12.4=0

We move all terms containing b to the left, all other terms to the right

-9.8b=-12.4

b=-12.4/-9.8

b=1+2.6/9.8

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