.2(2k-4)=3(k+2)-3k

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Solution for .2(2k-4)=3(k+2)-3k equation:


.2(2k-4)=3(k+2)-3k

We simplify the equation to the form, which is simple to understand 
.2(2k-4)=3(k+2)-3k

Reorder the terms in parentheses
+( + 0.4k-0.8)=3*(k+2)-3k

Remove unnecessary parentheses
 + 0.4k-0.8=+3+*(+k+2+)-3k

Reorder the terms in parentheses
 + 0.4k-0.8=+(+3k+6)-3k

Remove unnecessary parentheses
 + 0.4k-0.8=+3k+6-3k

We move all terms containing k to the left and all other terms to the right. 
 + 0.4k-3k+3k=+6 + 0.8

We simplify left and right side of the equation. 
 + 0.4k=+6.8

We divide both sides of the equation by 0.4 to get k. 
k=17

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