.12(y-2)+.08=.10y-.01(20)

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Solution for .12(y-2)+.08=.10y-.01(20) equation:


Simplifying
0.12(y + -2) + 0.08 = 0.10y + -0.01(20)

Reorder the terms:
0.12(-2 + y) + 0.08 = 0.10y + -0.01(20)
(-2 * 0.12 + y * 0.12) + 0.08 = 0.10y + -0.01(20)
(-0.24 + 0.12y) + 0.08 = 0.10y + -0.01(20)

Reorder the terms:
-0.24 + 0.08 + 0.12y = 0.10y + -0.01(20)

Combine like terms: -0.24 + 0.08 = -0.16
-0.16 + 0.12y = 0.10y + -0.01(20)

Multiply -0.01 * 20
-0.16 + 0.12y = 0.10y + -0.2

Reorder the terms:
-0.16 + 0.12y = -0.2 + 0.10y

Solving
-0.16 + 0.12y = -0.2 + 0.10y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-0.10y' to each side of the equation.
-0.16 + 0.12y + -0.10y = -0.2 + 0.10y + -0.10y

Combine like terms: 0.12y + -0.10y = 0.02y
-0.16 + 0.02y = -0.2 + 0.10y + -0.10y

Combine like terms: 0.10y + -0.10y = 0.00
-0.16 + 0.02y = -0.2 + 0.00
-0.16 + 0.02y = -0.2

Add '0.16' to each side of the equation.
-0.16 + 0.16 + 0.02y = -0.2 + 0.16

Combine like terms: -0.16 + 0.16 = 0.00
0.00 + 0.02y = -0.2 + 0.16
0.02y = -0.2 + 0.16

Combine like terms: -0.2 + 0.16 = -0.04
0.02y = -0.04

Divide each side by '0.02'.
y = -2

Simplifying
y = -2

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