.11/12b=32

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Solution for .11/12b=32 equation: 



.11/12b=32

We move all terms to the left:

.11/12b-(32)=0



Domain of the equation: 12b!=0

b!=0/12

b!=0

b∈R



We multiply all the terms by the denominator


-32*12b+.11=0

We add all the numbers together, and all the variables

-32*12b+0.11=0

Wy multiply elements

-384b+0.11=0

We move all terms containing b to the left, all other terms to the right

-384b=-0.11

b=-0.11/-384

b=0.11/384

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