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.0851-0.436x-0.44x^2=0
We add all the numbers together, and all the variables
-0.44x^2-0.436x+0.0851=0
a = -0.44; b = -0.436; c = +0.0851;
Δ = b2-4ac
Δ = -0.4362-4·(-0.44)·0.0851
Δ = 0.339872
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.436)-\sqrt{0.339872}}{2*-0.44}=\frac{0.436-\sqrt{0.339872}}{-0.88} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.436)+\sqrt{0.339872}}{2*-0.44}=\frac{0.436+\sqrt{0.339872}}{-0.88} $
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