.08(y-2)+.12y=.14y-.01(40)

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Solution for .08(y-2)+.12y=.14y-.01(40) equation:


.08(y-2)+.12y=.14y-.01(40)

We simplify the equation to the form, which is simple to understand
.08(y-2)+.12y=.14y-.01(40)

Reorder the terms in parentheses
+( + 0.08y-0.16)+.12y=.14y-.01*(40)

Remove unnecessary parentheses
+ 0.08y-0.16+.12y=+.14y-.01+*(+40+)

Reorder the terms in parentheses
+ 0.08y-0.16+.12y=.14y+(-0.4)

Remove unnecessary parentheses
+ 0.08y-0.16+.12y=+.14y-0.4

We move all terms containing y to the left and all other terms to the right.
+ 0.08y + 0.12y-0.14y=-0.4 + 0.16

We simplify left and right side of the equation.
+ 0.06y=-0.24

We divide both sides of the equation by 0.06 to get y.
y=-4

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