.04(3x-5)=.12(x+7)-1.04

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Solution for .04(3x-5)=.12(x+7)-1.04 equation: 


Simplifying
0.04(3x + -5) = 0.12(x + 7) + -1.04

Reorder the terms:
0.04(-5 + 3x) = 0.12(x + 7) + -1.04
(-5 * 0.04 + 3x * 0.04) = 0.12(x + 7) + -1.04
(-0.2 + 0.12x) = 0.12(x + 7) + -1.04

Reorder the terms:
-0.2 + 0.12x = 0.12(7 + x) + -1.04
-0.2 + 0.12x = (7 * 0.12 + x * 0.12) + -1.04
-0.2 + 0.12x = (0.84 + 0.12x) + -1.04

Reorder the terms:
-0.2 + 0.12x = 0.84 + -1.04 + 0.12x

Combine like terms: 0.84 + -1.04 = -0.2
-0.2 + 0.12x = -0.2 + 0.12x

Add '0.2' to each side of the equation.
-0.2 + 0.2 + 0.12x = -0.2 + 0.2 + 0.12x

Combine like terms: -0.2 + 0.2 = 0.0
0.0 + 0.12x = -0.2 + 0.2 + 0.12x
0.12x = -0.2 + 0.2 + 0.12x

Combine like terms: -0.2 + 0.2 = 0.0
0.12x = 0.0 + 0.12x
0.12x = 0.12x

Add '-0.12x' to each side of the equation.
0.12x + -0.12x = 0.12x + -0.12x

Combine like terms: 0.12x + -0.12x = 0.00
0.00 = 0.12x + -0.12x

Combine like terms: 0.12x + -0.12x = 0.00
0.00 = 0.00

Solving
0.00 = 0.00

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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