.03(4t-4)=.12(t-1)+.00

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Solution for .03(4t-4)=.12(t-1)+.00 equation: 


Simplifying
0.03(4t + -4) = 0.12(t + -1) + 0.00

Reorder the terms:
0.03(-4 + 4t) = 0.12(t + -1) + 0.00
(-4 * 0.03 + 4t * 0.03) = 0.12(t + -1) + 0.00
(-0.12 + 0.12t) = 0.12(t + -1) + 0.00

Reorder the terms:
-0.12 + 0.12t = 0.12(-1 + t) + 0.00
-0.12 + 0.12t = (-1 * 0.12 + t * 0.12) + 0.00
-0.12 + 0.12t = (-0.12 + 0.12t) + 0.00

Reorder the terms:
-0.12 + 0.12t = -0.12 + 0.00 + 0.12t

Combine like terms: -0.12 + 0.00 = -0.12
-0.12 + 0.12t = -0.12 + 0.12t

Add '0.12' to each side of the equation.
-0.12 + 0.12 + 0.12t = -0.12 + 0.12 + 0.12t

Combine like terms: -0.12 + 0.12 = 0.00
0.00 + 0.12t = -0.12 + 0.12 + 0.12t
0.12t = -0.12 + 0.12 + 0.12t

Combine like terms: -0.12 + 0.12 = 0.00
0.12t = 0.00 + 0.12t
0.12t = 0.12t

Add '-0.12t' to each side of the equation.
0.12t + -0.12t = 0.12t + -0.12t

Combine like terms: 0.12t + -0.12t = 0.00
0.00 = 0.12t + -0.12t

Combine like terms: 0.12t + -0.12t = 0.00
0.00 = 0.00

Solving
0.00 = 0.00

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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