.03(3t-4)=.09(t+1)-.21

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Solution for .03(3t-4)=.09(t+1)-.21 equation:


Simplifying
0.03(3t + -4) = 0.09(t + 1) + -0.21

Reorder the terms:
0.03(-4 + 3t) = 0.09(t + 1) + -0.21
(-4 * 0.03 + 3t * 0.03) = 0.09(t + 1) + -0.21
(-0.12 + 0.09t) = 0.09(t + 1) + -0.21

Reorder the terms:
-0.12 + 0.09t = 0.09(1 + t) + -0.21
-0.12 + 0.09t = (1 * 0.09 + t * 0.09) + -0.21
-0.12 + 0.09t = (0.09 + 0.09t) + -0.21

Reorder the terms:
-0.12 + 0.09t = 0.09 + -0.21 + 0.09t

Combine like terms: 0.09 + -0.21 = -0.12
-0.12 + 0.09t = -0.12 + 0.09t

Add '0.12' to each side of the equation.
-0.12 + 0.12 + 0.09t = -0.12 + 0.12 + 0.09t

Combine like terms: -0.12 + 0.12 = 0.00
0.00 + 0.09t = -0.12 + 0.12 + 0.09t
0.09t = -0.12 + 0.12 + 0.09t

Combine like terms: -0.12 + 0.12 = 0.00
0.09t = 0.00 + 0.09t
0.09t = 0.09t

Add '-0.09t' to each side of the equation.
0.09t + -0.09t = 0.09t + -0.09t

Combine like terms: 0.09t + -0.09t = 0.00
0.00 = 0.09t + -0.09t

Combine like terms: 0.09t + -0.09t = 0.00
0.00 = 0.00

Solving
0.00 = 0.00

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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