.03(2t+7)=.06(t+5)-.09

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Solution for .03(2t+7)=.06(t+5)-.09 equation: 


Simplifying
0.03(2t + 7) = 0.06(t + 5) + -0.09

Reorder the terms:
0.03(7 + 2t) = 0.06(t + 5) + -0.09
(7 * 0.03 + 2t * 0.03) = 0.06(t + 5) + -0.09
(0.21 + 0.06t) = 0.06(t + 5) + -0.09

Reorder the terms:
0.21 + 0.06t = 0.06(5 + t) + -0.09
0.21 + 0.06t = (5 * 0.06 + t * 0.06) + -0.09
0.21 + 0.06t = (0.3 + 0.06t) + -0.09

Reorder the terms:
0.21 + 0.06t = 0.3 + -0.09 + 0.06t

Combine like terms: 0.3 + -0.09 = 0.21
0.21 + 0.06t = 0.21 + 0.06t

Add '-0.21' to each side of the equation.
0.21 + -0.21 + 0.06t = 0.21 + -0.21 + 0.06t

Combine like terms: 0.21 + -0.21 = 0.00
0.00 + 0.06t = 0.21 + -0.21 + 0.06t
0.06t = 0.21 + -0.21 + 0.06t

Combine like terms: 0.21 + -0.21 = 0.00
0.06t = 0.00 + 0.06t
0.06t = 0.06t

Add '-0.06t' to each side of the equation.
0.06t + -0.06t = 0.06t + -0.06t

Combine like terms: 0.06t + -0.06t = 0.00
0.00 = 0.06t + -0.06t

Combine like terms: 0.06t + -0.06t = 0.00
0.00 = 0.00

Solving
0.00 = 0.00

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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