.(1)/(2)x+10=(1)/(4)x+54

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Solution for .(1)/(2)x+10=(1)/(4)x+54 equation: 



.(1)/(2)x+10=(1)/(4)x+54

We move all terms to the left:

.(1)/(2)x+10-((1)/(4)x+54)=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R





Domain of the equation: 4x+54)!=0

x∈R



We get rid of parentheses

.1/2x-1/4x-54+10=0

We calculate fractions


(.1*4x)/8x^2+(-2x)/8x^2-54+10=0

We add all the numbers together, and all the variables

(+.1*4x)/8x^2+(-2x)/8x^2-54+10=0

We add all the numbers together, and all the variables

(+.1*4x)/8x^2+(-2x)/8x^2-44=0

We multiply all the terms by the denominator


(+.1*4x)+(-2x)-44*8x^2=0

Wy multiply elements

-352x^2+(+.1*4x)+(-2x)=0

We get rid of parentheses

-352x^2+.1*4x-2x=0

We add all the numbers together, and all the variables

-352x^2-2x+.1*4x=0

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