-x2-12x+4=6x2

Solution for -x2-12x+4=6x2 equation:

-x2-12x+4=6x^2

We move all terms to the left:

-x2-12x+4-(6x^2)=0

determiningTheFunctionDomain
-6x^2-x2-12x+4=0

We add all the numbers together, and all the variables

-7x^2-12x+4=0

a = -7; b = -12; c = +4;
Δ = b2-4ac
Δ = -122-4·(-7)·4
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-16}{2*-7}=\frac{-4}{-14}
=2/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+16}{2*-7}=\frac{28}{-14}
=-2
$