-x2+4x-5=1

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Solution for -x2+4x-5=1 equation: 



-x2+4x-5=1

We move all terms to the left:

-x2+4x-5-(1)=0

We add all the numbers together, and all the variables

-1x^2+4x-6=0

a = -1; b = 4; c = -6;
Δ = b2-4ac
Δ = 42-4·(-1)·(-6)
Δ = -8
Delta is less than zero, so there is no solution for the equation

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