-x2+25x-24=0

Solution for -x2+25x-24=0 equation:

-x2+25x-24=0

We add all the numbers together, and all the variables

-1x^2+25x-24=0

a = -1; b = 25; c = -24;
Δ = b2-4ac
Δ = 252-4·(-1)·(-24)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-23}{2*-1}=\frac{-48}{-2}
=+24
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+23}{2*-1}=\frac{-2}{-2}
=1
$