-x-9(3x+3)=1/2(10x-10)+4

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Solution for -x-9(3x+3)=1/2(10x-10)+4 equation: 



-x-9(3x+3)=1/2(10x-10)+4

We move all terms to the left:

-x-9(3x+3)-(1/2(10x-10)+4)=0



Domain of the equation: 2(10x-10)+4)!=0

x∈R



We add all the numbers together, and all the variables

-1x-9(3x+3)-(1/2(10x-10)+4)=0

We multiply parentheses

-1x-27x-(1/2(10x-10)+4)-27=0

We multiply all the terms by the denominator


-1x*2(10x-10)+4)-27x*2(10x-10)+4)-(1-27*2(10x-10)+4)=0

We add all the numbers together, and all the variables

-1x*2(10x-10)+4)-27x*2(10x-10)+4)-(1-27*2(10x=0

Wy multiply elements

-2x^2(1+4)-27x*2(10x-10)-27*2(10x+4)-(1=0

We add all the numbers together, and all the variables

-2x^25-27x*2(10x-10)-27*2(10x+4)-(1=0

We add all the numbers together, and all the variables

-2x^25-27x*2(10x-10)-27*2(10x+4)=0

Wy multiply elements

-2x^25-54x^2(1-54x(1=0

We do not support expression: x^25

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