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-x-6=5/9x+8
We move all terms to the left:
-x-6-(5/9x+8)=0
Domain of the equation: 9x+8)!=0We add all the numbers together, and all the variables
x∈R
-1x-(5/9x+8)-6=0
We get rid of parentheses
-1x-5/9x-8-6=0
We multiply all the terms by the denominator
-1x*9x-8*9x-6*9x-5=0
Wy multiply elements
-9x^2-72x-54x-5=0
We add all the numbers together, and all the variables
-9x^2-126x-5=0
a = -9; b = -126; c = -5;
Δ = b2-4ac
Δ = -1262-4·(-9)·(-5)
Δ = 15696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{15696}=\sqrt{144*109}=\sqrt{144}*\sqrt{109}=12\sqrt{109}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-126)-12\sqrt{109}}{2*-9}=\frac{126-12\sqrt{109}}{-18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-126)+12\sqrt{109}}{2*-9}=\frac{126+12\sqrt{109}}{-18} $
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