-x-2(1-x)=-3(x+12)

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Solution for -x-2(1-x)=-3(x+12) equation: 



-x-2(1-x)=-3(x+12)

We move all terms to the left:

-x-2(1-x)-(-3(x+12))=0

We add all the numbers together, and all the variables

-x-2(-1x+1)-(-3(x+12))=0

We add all the numbers together, and all the variables

-1x-2(-1x+1)-(-3(x+12))=0

We multiply parentheses

-1x+2x-(-3(x+12))-2=0



We calculate terms in parentheses: -(-3(x+12)), so:

-3(x+12)

We multiply parentheses

-3x-36

Back to the equation:

-(-3x-36)



We add all the numbers together, and all the variables

x-(-3x-36)-2=0

We get rid of parentheses

x+3x+36-2=0

We add all the numbers together, and all the variables

4x+34=0

We move all terms containing x to the left, all other terms to the right

4x=-34

x=-34/4

x=-8+1/2

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