-x+4+7(x-2)=7(x-3)+12

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Solution for -x+4+7(x-2)=7(x-3)+12 equation: 



-x+4+7(x-2)=7(x-3)+12

We move all terms to the left:

-x+4+7(x-2)-(7(x-3)+12)=0

We add all the numbers together, and all the variables

-1x+7(x-2)-(7(x-3)+12)+4=0

We multiply parentheses

-1x+7x-(7(x-3)+12)-14+4=0



We calculate terms in parentheses: -(7(x-3)+12), so:

7(x-3)+12

We multiply parentheses

7x-21+12

We add all the numbers together, and all the variables

7x-9

Back to the equation:

-(7x-9)



We add all the numbers together, and all the variables

6x-(7x-9)-10=0

We get rid of parentheses

6x-7x+9-10=0

We add all the numbers together, and all the variables

-1x-1=0

We move all terms containing x to the left, all other terms to the right

-x=1

x=1/-1

x=-1

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