-x+3y+(k-3)z=0

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Solution for -x+3y+(k-3)z=0 equation:


Simplifying
-1x + 3y + (k + -3) * z = 0

Reorder the terms:
-1x + 3y + (-3 + k) * z = 0

Reorder the terms for easier multiplication:
-1x + 3y + z(-3 + k) = 0
-1x + 3y + (-3 * z + k * z) = 0

Reorder the terms:
-1x + 3y + (kz + -3z) = 0
-1x + 3y + (kz + -3z) = 0

Reorder the terms:
kz + -1x + 3y + -3z = 0

Solving
kz + -1x + 3y + -3z = 0

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add 'x' to each side of the equation.
kz + -1x + 3y + x + -3z = 0 + x

Reorder the terms:
kz + -1x + x + 3y + -3z = 0 + x

Combine like terms: -1x + x = 0
kz + 0 + 3y + -3z = 0 + x
kz + 3y + -3z = 0 + x
Remove the zero:
kz + 3y + -3z = x

Add '-3y' to each side of the equation.
kz + 3y + -3y + -3z = x + -3y

Combine like terms: 3y + -3y = 0
kz + 0 + -3z = x + -3y
kz + -3z = x + -3y

Add '3z' to each side of the equation.
kz + -3z + 3z = x + -3y + 3z

Combine like terms: -3z + 3z = 0
kz + 0 = x + -3y + 3z
kz = x + -3y + 3z

Divide each side by 'z'.
k = xz-1 + -3yz-1 + 3

Simplifying
k = xz-1 + -3yz-1 + 3

Reorder the terms:
k = 3 + xz-1 + -3yz-1

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