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-x+1/3x=0.8
We move all terms to the left:
-x+1/3x-(0.8)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
-1x+1/3x-0.8=0
We multiply all the terms by the denominator
-1x*3x-(0.8)*3x+1=0
We multiply parentheses
-1x*3x-2.4x+1=0
Wy multiply elements
-3x^2-2.4x+1=0
a = -3; b = -2.4; c = +1;
Δ = b2-4ac
Δ = -2.42-4·(-3)·1
Δ = 17.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.4)-\sqrt{17.76}}{2*-3}=\frac{2.4-\sqrt{17.76}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.4)+\sqrt{17.76}}{2*-3}=\frac{2.4+\sqrt{17.76}}{-6} $
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