-x+(3/4x)=-2

Solution for -x+(3/4x)=-2 equation:

-x+(3/4x)=-2

We move all terms to the left:

-x+(3/4x)-(-2)=0


Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-x+(+3/4x)-(-2)=0

We add all the numbers together, and all the variables

-1x+(+3/4x)+2=0

We get rid of parentheses

-1x+3/4x+2=0

We multiply all the terms by the denominator


-1x*4x+2*4x+3=0

Wy multiply elements

-4x^2+8x+3=0

a = -4; b = 8; c = +3;
Δ = b2-4ac
Δ = 82-4·(-4)·3
Δ = 112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{112}=\sqrt{16*7}=\sqrt{16}*\sqrt{7}=4\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{7}}{2*-4}=\frac{-8-4\sqrt{7}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{7}}{2*-4}=\frac{-8+4\sqrt{7}}{-8}
$