-u-(5+13u)+10=-6(4u+1)+7u

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Solution for -u-(5+13u)+10=-6(4u+1)+7u equation:



-u-(5+13u)+10=-6(4u+1)+7u
We move all terms to the left:
-u-(5+13u)+10-(-6(4u+1)+7u)=0
We add all the numbers together, and all the variables
-u-(13u+5)-(-6(4u+1)+7u)+10=0
We add all the numbers together, and all the variables
-1u-(13u+5)-(-6(4u+1)+7u)+10=0
We get rid of parentheses
-1u-13u-(-6(4u+1)+7u)-5+10=0
We calculate terms in parentheses: -(-6(4u+1)+7u), so:
-6(4u+1)+7u
We add all the numbers together, and all the variables
7u-6(4u+1)
We multiply parentheses
7u-24u-6
We add all the numbers together, and all the variables
-17u-6
Back to the equation:
-(-17u-6)
We add all the numbers together, and all the variables
-14u-(-17u-6)+5=0
We get rid of parentheses
-14u+17u+6+5=0
We add all the numbers together, and all the variables
3u+11=0
We move all terms containing u to the left, all other terms to the right
3u=-11
u=-11/3
u=-3+2/3

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