-t/5=(ln(1/1800))/(ln(2))

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Solution for -t/5=(ln(1/1800))/(ln(2)) equation: 


D( t )

ln(2) = 0

ln(2) = 0

ln(2) = 0

t_1 = ln(2)

ln(2) = 0

t_1 = 0

t należy do R

t in (-oo:+oo)

t belongs to the empty set

-t/5 = ln(1/1800)/ln(2)

t belongs to the empty set

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