-g+2(3/g)=-4(g+1)

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Solution for -g+2(3/g)=-4(g+1) equation: 



-g+2(3/g)=-4(g+1)

We move all terms to the left:

-g+2(3/g)-(-4(g+1))=0



Domain of the equation: g)!=0

g!=0/1

g!=0

g∈R



We add all the numbers together, and all the variables

-g+2(+3/g)-(-4(g+1))=0

We add all the numbers together, and all the variables

-1g+2(+3/g)-(-4(g+1))=0

We multiply parentheses

-1g+6g-(-4(g+1))=0



We calculate terms in parentheses: -(-4(g+1)), so:

-4(g+1)

We multiply parentheses

-4g-4

Back to the equation:

-(-4g-4)



We add all the numbers together, and all the variables

5g-(-4g-4)=0

We get rid of parentheses

5g+4g+4=0

We add all the numbers together, and all the variables

9g+4=0

We move all terms containing g to the left, all other terms to the right

9g=-4

g=-4/9

g=-4/9

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