-c(11c+4)=c

Solution for -c(11c+4)=c equation:

-c(11c+4)=c

We move all terms to the left:

-c(11c+4)-(c)=0

We add all the numbers together, and all the variables

-1c-c(11c+4)=0

We multiply parentheses

-11c^2-1c-4c=0

We add all the numbers together, and all the variables

-11c^2-5c=0

a = -11; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·(-11)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*-11}=\frac{0}{-22}
=0
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*-11}=\frac{10}{-22}
=-5/11
$