-b-20=3b+12

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Solution for -b-20=3b+12 equation: 



-b-20=3b+12

We move all terms to the left:

-b-20-(3b+12)=0

We add all the numbers together, and all the variables

-1b-(3b+12)-20=0

We get rid of parentheses

-1b-3b-12-20=0

We add all the numbers together, and all the variables

-4b-32=0

We move all terms containing b to the left, all other terms to the right

-4b=32

b=32/-4

b=-8

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