-b-(13+4b)=(-3-9b)+2

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Solution for -b-(13+4b)=(-3-9b)+2 equation: 



-b-(13+4b)=(-3-9b)+2

We move all terms to the left:

-b-(13+4b)-((-3-9b)+2)=0

We add all the numbers together, and all the variables

-b-(4b+13)-((-9b-3)+2)=0

We add all the numbers together, and all the variables

-1b-(4b+13)-((-9b-3)+2)=0

We get rid of parentheses

-1b-4b-((-9b-3)+2)-13=0



We calculate terms in parentheses: -((-9b-3)+2), so:

(-9b-3)+2

We get rid of parentheses

-9b-3+2

We add all the numbers together, and all the variables

-9b-1

Back to the equation:

-(-9b-1)



We add all the numbers together, and all the variables

-5b-(-9b-1)-13=0

We get rid of parentheses

-5b+9b+1-13=0

We add all the numbers together, and all the variables

4b-12=0

We move all terms containing b to the left, all other terms to the right

4b=12

b=12/4

b=3

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