-b(b-2)=10

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Solution for -b(b-2)=10 equation:


Simplifying
-1b(b + -2) = 10

Reorder the terms:
-1b(-2 + b) = 10
(-2 * -1b + b * -1b) = 10
(2b + -1b2) = 10

Solving
2b + -1b2 = 10

Solving for variable 'b'.

Reorder the terms:
-10 + 2b + -1b2 = 10 + -10

Combine like terms: 10 + -10 = 0
-10 + 2b + -1b2 = 0

Begin completing the square.  Divide all terms by
-1 the coefficient of the squared term: 

Divide each side by '-1'.
10 + -2b + b2 = 0

Move the constant term to the right:

Add '-10' to each side of the equation.
10 + -2b + -10 + b2 = 0 + -10

Reorder the terms:
10 + -10 + -2b + b2 = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -2b + b2 = 0 + -10
-2b + b2 = 0 + -10

Combine like terms: 0 + -10 = -10
-2b + b2 = -10

The b term is -2b.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2b + 1 + b2 = -10 + 1

Reorder the terms:
1 + -2b + b2 = -10 + 1

Combine like terms: -10 + 1 = -9
1 + -2b + b2 = -9

Factor a perfect square on the left side:
(b + -1)(b + -1) = -9

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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