-9x2+15x-6=0

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Solution for -9x2+15x-6=0 equation:



-9x^2+15x-6=0
a = -9; b = 15; c = -6;
Δ = b2-4ac
Δ = 152-4·(-9)·(-6)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-3}{2*-9}=\frac{-18}{-18} =1 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+3}{2*-9}=\frac{-12}{-18} =2/3 $

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