-9i+4(i-3)=(-4i)+3

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Solution for -9i+4(i-3)=(-4i)+3 equation: 



-9i+4(i-3)=(-4i)+3

We move all terms to the left:

-9i+4(i-3)-((-4i)+3)=0

We multiply parentheses

-9i+4i-((-4i)+3)-12=0



We calculate terms in parentheses: -((-4i)+3), so:

(-4i)+3

We get rid of parentheses

-4i+3

Back to the equation:

-(-4i+3)



We add all the numbers together, and all the variables

-5i-(-4i+3)-12=0

We get rid of parentheses

-5i+4i-3-12=0

We add all the numbers together, and all the variables

-1i-15=0

We move all terms containing i to the left, all other terms to the right

-i=15

i=15/-1

i=-15

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