-9=2(b-4)-(3+4b)

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Solution for -9=2(b-4)-(3+4b) equation: 



-9=2(b-4)-(3+4b)

We move all terms to the left:

-9-(2(b-4)-(3+4b))=0

We add all the numbers together, and all the variables

-(2(b-4)-(4b+3))-9=0



We calculate terms in parentheses: -(2(b-4)-(4b+3)), so:

2(b-4)-(4b+3)

We multiply parentheses

2b-(4b+3)-8

We get rid of parentheses

2b-4b-3-8

We add all the numbers together, and all the variables

-2b-11

Back to the equation:

-(-2b-11)



We get rid of parentheses

2b+11-9=0

We add all the numbers together, and all the variables

2b+2=0

We move all terms containing b to the left, all other terms to the right

2b=-2

b=-2/2

b=-1

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